average of first 24 multiples of 8
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a= 8
d= 8
n= 24
S24 = 24[2a + (n-1)d] / 2
= 12(16 + 23*8)
= 12 (16 + 184)
= 12 * 200
= 2400
Required Average = S24/24
= 2400/24
= 100
Hope it will help you
Please mark as brainliest if you liked the solution
d= 8
n= 24
S24 = 24[2a + (n-1)d] / 2
= 12(16 + 23*8)
= 12 (16 + 184)
= 12 * 200
= 2400
Required Average = S24/24
= 2400/24
= 100
Hope it will help you
Please mark as brainliest if you liked the solution
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