average of first 99 even numbers
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sum og n terms =n*(n+1)
avg = sum /total no of terms
average of n terms mean sum of all terms / (total no of terms)
sum of n terms in this case= 2*(1+2++3+...+99)=2* (99*100)/2=9900
now average=9900/99=100
avg = sum /total no of terms
average of n terms mean sum of all terms / (total no of terms)
sum of n terms in this case= 2*(1+2++3+...+99)=2* (99*100)/2=9900
now average=9900/99=100
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ujasyogi:
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Answer:
ask question 99+1=100
ans=100
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