Average of four consecutive odd numbers is 106 what is the third number in ascending order
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Let the sum of the four consecutive odd nos. = x + x +2 + x + 4 + x + 6
Then, 4x + 12 = 4 × 106 = 424
Therefore, x = 103, the numbers in ascending order is 103, 105, 107 and 109 and the third number is = 107.
Therefore answer 107.
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107 and
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