Average of n number is
a. the first number is increased by 2, second one is increased by 4, the third one is increased by 8 and so on. the average of the new numbers is
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sum of n numbers = na
a'ₓ = aₓ + 2ˣ
so ∑a'ₓ = ∑aₓ + ∑2ˣ = na + 2(2ⁿ-1)/(2-1)
average of n terms a'ₓ = a+ 2(2ⁿ-1)/n
a'ₓ = aₓ + 2ˣ
so ∑a'ₓ = ∑aₓ + ∑2ˣ = na + 2(2ⁿ-1)/(2-1)
average of n terms a'ₓ = a+ 2(2ⁿ-1)/n
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