Math, asked by Abhishek5087, 1 year ago

Average of squares of consecutive even numbers from 1 and 11

Answers

Answered by RishabhBansal
6
Hey!!!

____________

=> Observations = 4,16,36,64,100

Total Observations (n) = 5

Average = Sum of all Observations/n

=> Sum of all observations = 220

Average = 220/5

=> Average = 44

__________

Hope this helps ✌️
Answered by DeenaMathew
1

The average of squares of consecutive even numbers from 1 and 11 is 40.

Given:

The consecutive even numbers are from 1 and 11.

To Find:

Average of squares of consecutive even numbers from 1 and 11.

Solution:

To find the average of squares of consecutive even numbers from 1 and 11 we will follow the following steps:

As we know,

Even numbers from 1 to 11 are 2,4,6,8,10.

Now,

Square of even number = 2²= 4, 4²= 16, 6²= 36, 8² = 64, 10² = 100

Now,

Sum of squares of consecutive even numbers = 4 + 16 + 36 + 64 + 100 = 220

The average Sum of squares of consecutive even numbers is

 \frac{sum \: of \: squares \: of \: consecutive \: even \: numbers}{total \: numbers}  =  \frac{220}{5}= 40

The average of squares of consecutive even numbers from 1 and 11 is 40.

#SPJ2

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