Question

Average of two natural number is 5 greater than one of the numbers if the quoiten of numbers is 2,what are the numbers

Answer 1

Answer:

First natural number is 10 and second is 20

Explanation:

Let x and y be natural numbers such that x is less then y

        According to given condition

Average of x and y = (x + y)/2 = x + 5                 ..... (1)

Ratio of numbers = y/x = 2                                  ..... (2)

⇒                      y=2x                                       .....(3)                      

using equation (3) in (1) we get

                           (x + 2x)/2 = x + 5

Multiplying by 2 on both sides

                     x+2x=2x+10

Subtracting 2x from both sides

                        x=10

and using x=10 in equation (3) we get

                      y=2(10)=20

 Hence First natural number is 10 and second is 20

Answer 2

Answer:

"Let x and y be natural numbers such that x is less than y.

As per condition given, Average of x and y = (x + y)/2 = x + 5 .equation (1)

Again, Ratio of numbers = y/x = 2. Equation (2)

Or, y=2x. Equation (3)                      

Therefore with equation (3) in (1) we get

(x + 2x )/2 = x + 5

Multiplying by 2 on both sides we get, x+2x=2x+10

Subtracting 2x from both sides, x=10

Again, using x=10 in equation (3) we get

y=2(10)=20

Therefore, x = 10 and y = 20

"

Explanation: