If logmn=2logm then prove that m=n
Answers
Answered by
0
Solution:
log(mn) = 2logm
=> log(mn) = log m²
/* n log m = log mⁿ */
Remove log both sides , we get
=> mn = m²
Divide each term by 'm' we get
=> n = m
••••
Answered by
0
Answer:
Step-by-step explanation:
Attachments:
![](https://hi-static.z-dn.net/files/d97/2c390eb9a23b67e296593ea0b1f630da.jpg)
Similar questions