Question

Average of two natural number is 5 greater than one of the numbers if the quotient of number is 2 what are number

Answer 1

Solution:

Let a , b are two natural numbers.(b>a)

According to the problem given,

i) average of two natural numbers = (a+b)/2

ii) b/a = 2

b = 2a ----(1)

Now ,

(a+b)/2 - a = 5

=> (a+b-2a)/2 = 5

=> b - a = 10 ---(2)

substitute (1) in equation (2), we get

=> 2a - a = 10

=> a = 10

put a = 10 in equation (1) , we get

b = 2a = 2×10 = 20

Therefore,

Required two natural numbers are 10, 20

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