Question

aviž) r- - 20k + 1) x + k = 0
(ix) k?r? - 2 (2k – 1) x + 4 = 0
6) (k+1) x2 – 2 (k - 1) x + 1 = 0
xxi) 2x2 + kx + 3 = 0 [NCERT]
xxiii) x2 - 4kx + k = 0 [CBSE 2012]
(xxy) px (x – 3) + 9 = 0 [CBSE 2014]

Answer 1

Answer:

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