avogrado number present in how much amount of volume?
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22.7 litre approx
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CaptainSumit:
N * (density) * volume / (Molecular Weight). N is a constant called Avogadro's number and its equal to 6.022*1023 atoms/mole
The number of atoms of ANY substance in a volume is: # of atoms :--- N * (density) * volume / (Molecular Weight). . . . N is a constant called Avogadro's number and its equal to 6.022*1023 atoms/mole
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approximately 22.7litre
this is the amount of volume...
this is the amount of volume...
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