Math, asked by rakshanap98, 8 months ago

ax+1
Let a ' b satisfy a² + 1 = 6a, 62 + 1 = 6b. Then, the quadratic equation whose roots are
8x2 - 8x - 1 = 0
8x2 - 8x + 1 = 0
8.x2 + 8x - 1 = 0
8x2 + 8x + 1 = 0​

Answers

Answered by yaduvanshitab
5

Answer:

8x^2+8x-1= 0

it is correct.

hope this helps you.

pls mark as brainliest.

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