Math, asked by umertalal778, 1 year ago


Solve the following equation.​

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Answers

Answered by adityaprabhakar2004
2

Answer:

Given

 {x}^{ - 2}  - 10 =  {3x}^{ - 1}

 \frac{1}{ {x}^{2} }  - 10 =  \frac{3}{x}

 \frac{1}{ {x}^{2} }  -   \frac{3}{x}  = 10

Taking LCM

 \frac{1 - 3x}{ {x}^{2} }  = 10

1 - 3x = 10 {x}^{2}

Taking terms on LHS to RHS

10 {x}^{2} + 3x -  1 = 0

Factorising the equation, we get

10 {x}^{2} + 5x - 2x - 1 = 0

5x(2x + 1) - 1(2x + 1) = 0

(5x - 1)(2x + 1) = 0

x =  \frac{1}{5} \: or \:  \frac{ - 1}{2}

Hope u understood

감사합니다

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