Question

Solve the following equation.​

Answer 1

Answer:

Given

${x}^{ - 2} - 10 = {3x}^{ - 1}$

$\frac{1}{ {x}^{2} } - 10 = \frac{3}{x}$

$\frac{1}{ {x}^{2} } - \frac{3}{x} = 10$

Taking LCM

$\frac{1 - 3x}{ {x}^{2} } = 10$

$1 - 3x = 10 {x}^{2}$

Taking terms on LHS to RHS

$10 {x}^{2} + 3x - 1 = 0$

Factorising the equation, we get

$10 {x}^{2} + 5x - 2x - 1 = 0$

$5x(2x + 1) - 1(2x + 1) = 0$

$(5x - 1)(2x + 1) = 0$

$x = \frac{1}{5} \: or \: \frac{ - 1}{2}$

Hope u understood

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