Question

Ax 2 -28x+49=0 has equal roots then the value of a i

Answer 1

sorry I didn't know the answer to the question

Answer 2

The value of A is 4.

Step-by-step explanation:

Given : Quadratic equation $Ax^2-28x+49=0$ has equal roots.

To find : The value of A ?

Solution :

When the roots of the equation $ax^2+bx+c=0$ are equal then the discriminant is 0 i.e. $D=0$

$b^2-4ac=0$ ....(1)

In quadratic equation $Ax^2-28x+49=0$,

a=A, b=-28 and c=49

Substitute in (1),

$(-28)^2-4(A)(49)=0$

$784-196A=0$

$196A=784$

$A=\frac{784}{196}$

$A=4$

Therefore, the value of A is 4.

#Learn more

Find the value of m so that quadratic equation x(x-7)+49=0 has equal roots nature of roots

https://brainly.in/question/2072181