Math, asked by dkr3, 1 year ago

ax and cy are height of parallelogram abcd.whose area is 28/3.what are the length of xa and cy.


faizaankhanpatp3bt9p: i any side given in this question

Answers

Answered by faizaankhanpatp3bt9p
27
Area of Parallelogram =28/3cm.sq.
Base×Height=28/3
= 7× h =28/3
h= 28/(7×3)
h=4/3 cm

therefore XA = 4/3cm 
Now take CB as a base nd CY as height 
Area of Parallelogram=28/3cm.sq.
Base×Height= 28/3
4×h = 28/3
= h= 28/(4×3)
h= 7/3cm 
therefore CY = 7/3cm
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faizaankhanpatp3bt9p: hope this was helpful
Answered by Anonymous
12
Hi there!

Given that, Area of parallelogram = 28/3 cm² 

∵ Area of Parallelogram = 28/3 cm²

For finding XA:

Base × Height = 28/3 cm²

AB × XA = 28/3 cm² 

7 × XA = 28/3 cm²

XA = 28/(7×3)

XA = 4/3 cm
 
For finding CY:

Base × Height = 28/3 cm²

BC × CY = 28/3 cm²

4 × CY = 28/3 cm²

CY = 28/(4×3)

CY= 7/3 cm 

Hence,
XA = 4/3 cm & CY = 7/3 cm

Cheers!
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