(ax/b)-(by/a)=a+b and. ax-by=2ab find the value of a and b
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Given system of equations:
{ax}/{b}-{by}/{a}=a+b ...................... (1)
ax-by=2ab ....................(2)
from equation (2), we get
ax=2ab+by
x={2ab+by}/{a} ......... (3)
Put, this value of eqn (3) in eqn(1)
(a* {2ab+by}/{a})/{b}-{by}/{a}=a+b
{2ab+by}/{b}-{by}/{a}=a+b
{a(2ab+by)-b^2y}/{ab}=a+b
2a^2b-aby+b^2y=ab(a+b)
2a^2b+(ab-b^2)y=a^2b+ab^2
(ab-b^2)y=a^2b+ab^2-2a^2b
b(a-b)y=ab^2-a^2b
b(a-b)y=-ab(a-b)
y={-ab(a-b)}/{b(a-b)}
y=-a
Now, Put value of y in eqn (3)
x={2ab-ba}/{a}
x={ab}/{a}
x=b
Therefore, x = b & y = -a
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