(ax+b) find the derivative
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Answered by
3
heya user
suppose y=(ax+b)
then it's derivative will be
dy/ dx=a
hope it helps you....
for further query comment
suppose y=(ax+b)
then it's derivative will be
dy/ dx=a
hope it helps you....
for further query comment
aartienterprispc7mun:
thanks
Answered by
1
Answer:
f'(x)=a2√ax+b
Explanation:
differentiate using the chain rule
Reminder ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯∣∣∣22dydx=dydu×dudx22∣∣∣−−−−−−−−−−−−−−−−−−−−→(A)
let u=ax+b⇒dudx=a
⇒y=u12⇒dydu=12u−12
substitute into (A), changing u back into terms of x
⇒dydx=12u−12.a
=a2√ax+b
f'(x)=a2√ax+b
Explanation:
differentiate using the chain rule
Reminder ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯∣∣∣22dydx=dydu×dudx22∣∣∣−−−−−−−−−−−−−−−−−−−−→(A)
let u=ax+b⇒dudx=a
⇒y=u12⇒dydu=12u−12
substitute into (A), changing u back into terms of x
⇒dydx=12u−12.a
=a2√ax+b
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