Derive the first equasion of motion by graphical method
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solve in fig...
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solve in fig...
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YubendraShakya:
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Hello friend
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⭐⭐⭐HERE IS YOUR ANSWER⭐⭐⭐
The first equation of is that the relation between velocity and time.
v = u + at
So let's understand by the graphical method.
I will upload an image in this answer and that is our graph.
⭐Velocity -time graph:
Velocity and time graph shows the change in velocity with time of a uniformly accelerated object. The object starts from the point D in the graph with velocity v.Its velocity keeps increasing and after time t.It reaches the point B on the graph.
The initial velocity of the object = u = OD
The final velocity of the object= v = OC
Time= t = OE
NOW,we know that,
Acceleration (a) = Change in velocity/Time
= final velocity - initial velocity/time
= OC - OD/t
hence,
CD = at .......(i) (OC - OD = CD)
From the graph.......BE = AB + AE
therefore,
v = CD + OD .....( AB = CD and AE = OD)
v = at + u .......(from i )
v = u + at
Now ,we have proved..
This is the first equation of motion.
I hope this helps you.
Thanks.
----------------
⭐⭐⭐HERE IS YOUR ANSWER⭐⭐⭐
The first equation of is that the relation between velocity and time.
v = u + at
So let's understand by the graphical method.
I will upload an image in this answer and that is our graph.
⭐Velocity -time graph:
Velocity and time graph shows the change in velocity with time of a uniformly accelerated object. The object starts from the point D in the graph with velocity v.Its velocity keeps increasing and after time t.It reaches the point B on the graph.
The initial velocity of the object = u = OD
The final velocity of the object= v = OC
Time= t = OE
NOW,we know that,
Acceleration (a) = Change in velocity/Time
= final velocity - initial velocity/time
= OC - OD/t
hence,
CD = at .......(i) (OC - OD = CD)
From the graph.......BE = AB + AE
therefore,
v = CD + OD .....( AB = CD and AE = OD)
v = at + u .......(from i )
v = u + at
Now ,we have proved..
This is the first equation of motion.
I hope this helps you.
Thanks.
Attachments:
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