Question

(ax+by)²+(bx-ay)² .... factorise​

Answer 1

Please find the attachment

Answer 2

Step-by-step explanation:

$= {a}^{2} {x}^{2} + 2axby + {b}^{2} {y}^{2} + {b}^{2} {x}^{2} - 2axby + {a}^{2} {y}^{2} \\ = {a}^{2} {x}^{2} + {b}^{2} {y}^{2} + {b}^{2} {x}^{2} + {a}^{2} {y}^{2} \\ = {a}^{2} ( {x}^{2} + {y}^{2} ) + {b}^{2} ( {x}^{2} + {y}^{2} ) \\ = ( {x}^{2} + {y}^{2} )( {a}^{2} + {b}^{2} )$