find the coordinates of the point of trisection
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Given:- A line segment joining the points A(2,−2) and B(−7,4).
Let P and Q be the points on AB such that,
AP=PQ=QB
Therefore,
P and Q divides AB internally in the ratio 1:2 and 2:1 respectively.
As we know that if a point (h,k) divides a line joining the point (x1,y1) and (x2,y2) in the ration m:n, then coordinates of the point is given as-
(h,k)=(m+nmx2+nx1,m+nmy2+ny1)
Therefore,
Coordinates of P=(1+21×(−7)+2×2,1+21×4+2×(−2))=(−1,0)
Coordinates of Q=(1+22×(−7)+1×2,1+22×4+1×(−2))=(−4,2)
Therefore, the coordinates of the points of trisection of the line segment joining A and B are (−1,
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