Math, asked by nandanijaiswal962, 8 months ago

ax+ by = c
bx+
ay = (1+c ) by substitution method ......​

Answers

Answered by rajivrtp
1

Step-by-step explanation:

ax+by = c..........(1)

bx+ay = 1+c......(2)

from (1) by = c-ax

=> y =( c-ax) /b

putting in (2)

bx + a(c-ax)/b = 1+c

bx+ac/b-a²x/b = 1+c

(b-a²/b) x = 1+c -(ac/b)

x = b+bc-ac / ( b²-a²)

= b/(b²-a²) +c/(b+a)

from(1)

y = c/b-a[ b/(b²-a²) +c/(b+a)]/b

= c/b - a/(b²-a²)+ac(b+a,)/b

hope this helps you

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