ax+ by = c
bx+
ay = (1+c ) by substitution method ......
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Step-by-step explanation:
ax+by = c..........(1)
bx+ay = 1+c......(2)
from (1) by = c-ax
=> y =( c-ax) /b
putting in (2)
bx + a(c-ax)/b = 1+c
bx+ac/b-a²x/b = 1+c
(b-a²/b) x = 1+c -(ac/b)
x = b+bc-ac / ( b²-a²)
= b/(b²-a²) +c/(b+a)
from(1)
y = c/b-a[ b/(b²-a²) +c/(b+a)]/b
= c/b - a/(b²-a²)+ac(b+a,)/b
hope this helps you
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