Ax gram of metal gives y g of metal oxide on
complete combustion. The equivalent weight of
metal is
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Answer:
Weight of metal= x gm and weight of oxide= y gm
∴ Oxygen consumed= (y−x)gm..
Since (y−x) gm of oxygen combines with x gm of metal.
∴8gm of oxygen will combine with 8 x ÷ y-x gm
of metal
Hence equivalent weight of metal= x ÷ y-x × 8
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