Question

ax sinbx dx
=
a.
eax
(a sinbx – b cosbx)
a2 +b2
b.
eax
(a cosbx – b sinbx)
a2+b2
ex
(a cosbx + b sinbx)
a2+b2
d.
eax
(a sinbx + b cosbx)
a2+b2​

Answer 1

Answer:

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