Question

ax²+3x²-3 and 2x³-5x+k are divided by (x-4) leave same remainder. Find k.

Pls it's very important.​

Answer 1

R1 = a(4)3+ 3(4)2 − 3 = 64a + 45 …(i)

R2 = 2(4)3 − 5(4) + a = 128 − 20 +a = 108 + a …(ii)

Given: 2R1−R2= 0

∴2(64a+45) − (108+a) = 0

(from (i) and (ii))

⇒ 128a + 90 − 108 − a = 0

⇒ 127a = 18

a = 18/127

Answer 2

Answer:

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