Question

ax²+ 4a²x-3bx-12ab=0

Answer 1

ax² +4a²x -3bx -12ab =0

ax(x+4a) -3b(x +4a) =0

(ax-3b) (x+4a) =0

ax = 3b Or x = -4a

x = 3b/a Or x = -4a

I hope this will help you

-by ABHAY

Answer 2

$ax {}^{2} + 4a {}^{2} x - 3bx - 12ab = 0$

$ax(x + 4a) - 3b(x + 4a) = 0$

$(ax - 3b)(x + 4a) = 0$

x = 3b/a and -4a


Thanks