Question

ax2 + bx2 + 2a + 2b. Factorise by grouping.
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Answer 1

Required Answer:-

Given To Factorise:

• ax² + bx² + 2a + 2b

Solution:

We have,

= ax² + bx² + 2a + 2b

Taking x² as common, we get,

= x²(a + b) + 2a + 2b

Taking 2 as common,

= x²(a + b) + 2(a + b)

Now take (a + b) as common,

= (a + b)(x² + 2)

★ Hence, the factorised form of the polynomial is (a + b)(x² + 2)

Answer:

• Required Answer - (a + b)(x² + 2)

Answer 2

Answer:

ax² + bx² + 2a + 2b

Step-by-step explanation:

x² (a + b) + 2 ( a + b )

= ( a + b ) ( x² + 2 )

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