Question

ax2y - Bxyz -ax2z + bxy2​

Answer 1

Factorise:

ax²y - bxyz - ax²z + bxy²

Answer:

x( y - z )( ax + by )

Step by step explanation:

Taking x as comman:

⟹ x ( axy - byz - axz + by² )

Rearrange the terms inside the brackets.

⟹ x ( axy - axz + by² - byz )

Take ax in common in the first two term ( inside the brackets )

⟹ x { ax( y - z ) + by² - byz }

Take by in common in the third and fourth term ( inside the brackets )

⟹ x { ax( y - z ) + by( y - z) }

Take ( y - z ) in common inside the brackets.

⟹ x { ( y - z ) ( ax + by ) }

The factors are : x, (y - z) and ( ax + by )