Math, asked by wallnutmilk, 1 year ago

Ayushi’s mother is thrice as old as her. After 10 years , her age will be twice as Ayushi. Find their present ages. Also do the verification.

Answers

Answered by anirudhsingh87
0

Let the mother age be x

Let the Ayushi age be y

x=3y...(1)eq

After the 10 yrs

x+10=2(y+10)

x+10=2y+20

putting x value here

3y+10=2y+20

3y-2y=20-10

y=10

Hence Ayushi present age =10 yrs

Mother age =x=3y

x=3y

x=3*10

x=30yrs

hence mother age is 30yrs

Hope this helps to you!!!!!


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Answered by oshoraa
0

Answer:

Step-by-step explanation:

Let Ayushi's age = x

Her Mother = 3 x

after 10 years

mother age = 2 x Ayushi's age

3 x + 10       =  2  (x + 10)

3 x  + 10      =  2 x  + 20

3 x  - 2 x     =   20 - 10

           x     =   10

so, Ayushi age = 10

mother age  = 30

after 10,   Ayushi age = 20, mother age = 40

Verification

Ayushi’s mother is thrice as old as her.

 so, Ayushi = 10,  mother = 3 x 10 = 30

After 10 years , her age will be twice as Ayushi

Ayushi = 10 +10 = 20,   Mother = 20 x 2 = 40

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