Question

(b) 0.5 mole of water molecules?
10.) Calculate the number of molecules of sulphur (S) present in
16 g of solid sulphur.​

Answer 1

Explanation:

M

$\frac{N}{N0} = \frac{m}{M}$

N=no. of molecules/ions/atoms

N0=Avogadro no.(=6.022×10^23)

m=given mass in gram

M=molar mass (for Sulphur M=32)

$N = \frac{m}{M } \times N0 \\N = \frac{16}{32} \times 6.02 \times {10}^{23} \\ N = 3.01 \times {10}^{23} molecules$