Question

(b+1) and (b-1) are the sides of a right triangle then other side is​

Answer 1

Answer:

x=√b+1 is the answer by Pythagoras theorem in maths hypotenuse square us equal to base square plus perpendicular square.

Answer 2

Answer:

$\sqrt{2 {b}^{2} + 2}$

Step-by-step explanation:

If the given sides were taken as opposite and adjacent sides of a right angled triangle, then the other side i.e..., hypotenuse side is

$x = \sqrt{ {opposite \: side}^{2} + {adjcent \: side}^{2} }$

$x = \sqrt{ {(b + 1)}^{2} + {(b - 1)}^{2} }$

$x = \sqrt{ {b}^{2} + 1 + b + {b}^{2} + 1 - b }$

$x = \sqrt{2 {b}^{2} + 2 }$

So, it's the answer