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18. The angle of elevation of the top of a building 150 m high, from a point on the
ground is 45º Draw the suitable diagram for given information.
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Let the height of building of 150m is AB the angle of elevation is 45 from point C and angle B = 90
Now, in right angled triangle ABC
AB/BC = tan45
150/BC = 1. (tan45 = 1)
150 = BC
So, distance of building from given point is 150m.
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