Question

b^2-14b+48=0 please solve the question ​

Answer 1

Answer:

${b}^{2} - 14b + 48 = 0 \\ = > {b}^{2} - 8b - 6b + 48 = 0 \\ = > b(b - 8) - 6(b - 8) = 0 \\ = > (b - 8)(b - 6) = 0 \\ = > b = 8 \: \: or \: \: b = 6$

Answer 2

Answer:

Here's your answer;

b²- 14b + 48 = 0

This implies,

Step 1. Using prime factorisation method

b² - 8b - 6b + 48 = 0 (After prime factorisation step)

now,

Step 2. Picking out commons

b( b - 8 ) - 6( b - 8 ) = 0 (After taking common)

This implies,

Step 3. Putting the commons together to get an equation

( b - 6 )( b - 8 ) = 0

Or,

The answer is b = 6, 8

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