Question

b=√2,c=√3,B=45° find the angle C in triangle ABC

Answer 1

Answer:

use sine rule

a/sinA=b/sinB=c/sinC

√2/1/√2=√3/sinC

2=√3/sinC

sinC=√3/2

C=60degrees

Answer 2

method 1

b/c=root 2/root 3

SinB/sin C=root 2/root 3

SinC=sin 45(root3)/roo2=root3/2

C=60

or

method 2

b/c=√2/√3

sinB/sinC=√2/√3

sin45°/sinC=√2/√3

sinC=sin45°(√3)/√2

sinC=√3/√2

sinC=60°

Therefore, C=60°