Question

B
2. In the given figure, if D is mid-point of
BC, the value of

$\frac{tan x}{tany} in degree$

​(A) 1/3
(B) 1
(C) 2
(D) 1/2

Answer 1

Answer:

(c). 2

Step-by-step explanation:

In △ACD

tanx∘ = CD/AC

In △ABC

tany ∘ =CB/AC

Now D is midpoint of CB

∴CB=2CD

Dividing (i) by (ii)

⇒

tanx∘/tany∘ = AC/CD/AC/CB =CB/CD= 2CD/CD=2