b) [288 + (-12)] + (-4) = 288 = [(-12) - (-4)]
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Giventhat2x=4y=8z−−(1)and,xyz=288−−−(2)usingequn(1)weget2x=(22)y=(23)z⇒2x=22y=23z[∴(am)n=amn]⇒x=2y=3z⇒x=2yandx=3z⇒x=2yandx=3z∴y=2xandz=3xNow,subsitute(y=2x)&(z=3x)inequn(2)
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