Question

(b) 3(2x - 1) - 2x = -3
(d) 6 + 2(3x + 6) = 3(x + 2)
(f) 3(2y – 4) + 3y = 5(y – 4)​

Answer 1

Answer:

$3(2x - 1) - 2x = - 3 \\ = > 6x - 3 - 2x = - 3 \\ = > 4y - 3 = - 3 \\ = > 4y = - 3 + 3 \\ = > 4y = 0 \\ = > y = \frac{0}{4} \\ = > y = 0 \\ \\ 6 + 2(3x + 6) = 3(x + 2) \\ = > 6 + 6x + 12 = 3x + 6 \\ = > 18 + 6x = 3x + 6 \\ = > 6x - 3x = 6 - 18 \\ = > 3x = - 12 \\ = > x = \frac{ - 12}{3} \\ = > x = - 4 \\ \\ 3(2y - 4) + 3y = 5(y - 4) \\ = > 6y - 12 + 3y = 5y - 20 \\ = > 9y- 12 = 5y - 20 \\ = > 9y - 5y = - 20 + 12 \\ = > 4y = - 8 \\ = > y = \frac{ - 8}{4} \\ = > y = - 2$

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Answer 2

Step-by-step explanation:

(b) $\sf (b)\: 3(2x-1)-2x=-3 \\ 6x-3-2x=-3 \\ 4x-3=-3 \\ 4x=0 \\ x=0 \\ \\ \sf (d) \: 6+2(3x+6)=3(x+2) \\ 6+6x+12=3x+6 \\ 6x+18=3x+6 \\ 6x-3x=-18+6 \\ 3x=-12 \\ x=-4 \\ \sf (f) \; 3(2y-4)+3y=5(y-4) \\ 6y-12+3y=5y-20 \\ 9y-12=5y-20 \\ 9y-5y=12-20 \\ 4y=-8 \\ y=-2$

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