Question

b) 3(x2 - 9)(x + 4) and 12(x - 3)2​

Answer 1

27

PREMISES

4(x-3)-3(x+2)=5+2(x+2)

CALCULATIONS

(1) 4(x-3)-3(x+2)=5+2(x+2) (Expand the polynomial and then simplify to solve for x if desired)

(2) 4x-12–3x-6=5+2x+4

(3) (4x-3x)-(12+6)=(5+4)+2x

(4) 1x-18=9+2x

(5) x-18=9+2x

(6) (x-x)-(18+9)=9–9+2x-x

(7) 0–27=0+x

(8) x=

-27

PROOF

If x=-27, then the equations

(1) [4(-27)-3(–27)]-(12+6)=(5+4)+2(-27)

(2) -27–18=9+-54 and

(3) -45=-45 establish that x=-27 is a root of the polynomial 4(x-3)-3(x+2)=5+2(x+2) in the premises above

C.H.

Hope it helps

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