Question

b) 3(y + 1) – 2(y + 1) = 5 by transposing method​

Answer 1

Answer:

y=4

Step-by-step explanation:

3×(y+1) -2×(y+1) = 5

3×y + 3×1 - 2×y -2×1 =5

3y + 3 -2y - 2 = 5

3y -2y +3 - 2 = 5

y+ 1 = 5

y + 1 -1 = 5-1

y = 4

Answer 2

Answer:

3(y+1)=5+2(y+1) transposing _2(y+1) to the L.H.S

3(y+1)=5+2(y+1)

3(y+1)=5+2y+2=9y

3(y+1)=9y

3y+3=9y

3y_9y=_3

_6=-3