Math, asked by ak85271148, 7 months ago

(b) 3y-5z=4 and 9y-2z=7 solve this question with deletion method​

Answers

Answered by Anonymous
35

Equations:-

  • 3y - 5z = 4.....(i)
  • 9y - 2z = 7.......(ii)

Multiplying 3 to the first equation,we get

=> 9y - 15z = 12

=> 9y - 2z = 7

=> ⠀⠀- 13z = 5

=> ⠀⠀⠀z = \frac{5}{-13}

Putting the value of z in equation (i), we get

=> 3y - 5z = 4

=> 3y - 5 × \: \frac{5}{-13} = 4

=> 3y \frac{-25}{-13} = 4

=> 3y = 4 × \frac{13}{25}

=> 3y =  \frac{52}{25}

=> y =  \frac{52}{25 × 3}

=> y =  \frac{52}{75}

Answered by Lueenu22
0

Step-by-step explanation:

Equations:-

3y - 5z = 4.....(i)

9y - 2z = 7.......(ii)

Multiplying 3 to the first equation,we get

=> 9y - 15z = 12

=> 9y - 2z = 7

=> ⠀⠀- 13z = 5

=> ⠀⠀⠀z = \frac{5}{-13}

−13

5

Putting the value of z in equation (i), we get

=> 3y - 5z = 4

=> 3y - 5 × \: \frac{5}{-13}5×

−13

5

= 4

=> 3y \frac{-25}{-13}

−13

−25

= 4

=> 3y = 4 × \frac{13}{25}4×

25

13

=> 3y = \frac{52}{25}

25

52

=> y = \frac{52}{25 × 3}

25×3

52

=> y = \frac{52}{75}

75

52

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