Question

(b) 3y-5z=4 and 9y-2z=7 solve this question with deletion method​

Answer 1

Equations:-

• 3y - 5z = 4.....(i)
• 9y - 2z = 7.......(ii)

Multiplying 3 to the first equation,we get

=> 9y - 15z = 12

=> 9y - 2z = 7

=> ⠀⠀- 13z = 5

=> ⠀⠀⠀z = $\frac{5}{-13}$

Putting the value of z in equation (i), we get

=> 3y - 5z = 4

=> 3y - $5 × \: \frac{5}{-13}$ = 4

=> 3y $\frac{-25}{-13}$ = 4

=> 3y = $4 × \frac{13}{25}$

=> 3y = $\frac{52}{25}$

=> y = $\frac{52}{25 × 3}$

=> y = $\frac{52}{75}$

Answer 2

Step-by-step explanation:

Equations:-

3y - 5z = 4.....(i)

9y - 2z = 7.......(ii)

Multiplying 3 to the first equation,we get

=> 9y - 15z = 12

=> 9y - 2z = 7

=> ⠀⠀- 13z = 5

=> ⠀⠀⠀z = \frac{5}{-13}

−13

5

Putting the value of z in equation (i), we get

=> 3y - 5z = 4

=> 3y - 5 × \: \frac{5}{-13}5×

−13

5

= 4

=> 3y \frac{-25}{-13}

−13

−25

= 4

=> 3y = 4 × \frac{13}{25}4×

25

13

=> 3y = \frac{52}{25}

25

52

=> y = \frac{52}{25 × 3}

25×3

52

=> y = \frac{52}{75}

75

52