Math, asked by yogesstha, 3 months ago

b) 7^(5x - 4) × a^(4x – 3) = 7^(2x - 3) × a^(x-2)​

Answers

Answered by dsah9628
4

Step-by-step explanation:

Here,

7^(5x - 4) × a^(4x – 3) = 7^(2x - 3) × a^(x-2)

or, 7^(5x-4) /7^(2x-3) = a^(x-2) /a^(4x-3)

or, 7^(5x-4-2x+3) = a^(x-2-4x+3)

or, 7^(3x-1) = a^(-3x+1)

or, 7^(3x-1) = a^-(3x-1)

or, 7^(3x-1) = 1/a^(3x-1)

or, 7^(3x-1) . a^(3x-1) = 1

or, (7a)^(3x-1) = (7a)^0

or, 3x-1 = 0

or, 3x = 1

i.e. x = 1/3

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