B)+7
The probability of getting 53 Sundays in a leap year is
A) -
347
07 77
00 7
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The probability of getting 53 Sunday is
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0
Answer:
event: getting 53 sundays in a leap year
a leap year has 52 weaks and 2 odd days
2 days can be as (sun,mon& mon,tue.....&sat,sun)
hence n(e)= 2
n(s)=7
probability getting sunday is 2/7
hope it helps
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