Math, asked by suchethprakash, 10 months ago

B)+7
The probability of getting 53 Sundays in a leap year is
A) -
347
07 77
00 7​

Answers

Answered by student5649
0

The probability of getting 53 Sunday is

 \frac{2}{7}

Answered by kavyasreekammaowvuv7
0

Answer:

event: getting 53 sundays in a leap year

a leap year has 52 weaks and 2 odd days

2 days can be as (sun,mon& mon,tue.....&sat,sun)

hence n(e)= 2

n(s)=7

probability getting sunday is 2/7

hope it helps

mark me as brainliest

Similar questions