(b) 80 J of heat is produced each second when current is passed through a 5Ω resistance. Find the
potential difference across the resistor.
Answers
Answered by
48
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Given,
Heat produced (E) = 80 J
Time(t) = 1 sec
Resistance = 5Ω
We know,
E = I²Rt
80 = I² * 5 * 1
16 = I²
4 = I
or I = 4 A
Now,
V = IR
V = 4*5
V = 20 V
Hope It Helps You! ☺☻☺
Given,
Heat produced (E) = 80 J
Time(t) = 1 sec
Resistance = 5Ω
We know,
E = I²Rt
80 = I² * 5 * 1
16 = I²
4 = I
or I = 4 A
Now,
V = IR
V = 4*5
V = 20 V
Hope It Helps You! ☺☻☺
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Answered by
1
H=80J
T=1sec
R =5 ohms
H=I^RT
80=I^5*1
80=I^5
I^=80/5
I^=16
I=root of 16
I=4A
V=IR
=4*5
=20V
T=1sec
R =5 ohms
H=I^RT
80=I^5*1
80=I^5
I^=80/5
I^=16
I=root of 16
I=4A
V=IR
=4*5
=20V
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