(а+b+с)=9
b(a+b+c) = 16
с(а+b+c) =144
a =?
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Given ,
- (а+b+с)=9
- b(a+b+c) = 16
- с(а+b+c) =144
To find :— a = ?
Now ,
b(a+b+c) = 16
=> b × 9 = 16
=> b = 16/9
And
с(а+b+c) =144
=> c × 9 = 144
=> c = 144/9
=> c = 16
Again ,
а+b+с = 9
=> a + (16/9) + 16 = 9
=> a = 9 - 16 - (16/9)
=> a = 9 - (160/9)
=> a = - 79/9
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