Math, asked by raj221802, 2 months ago

(b-a)/(a-c)+(c-b)/(b-a)+(a-c)/(c-b)
calculate this
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Answers

Answered by anu560070
1

Step-by-step explanation:

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Attachments:
Answered by chetanajha8928
0

Answer:

Equation at the end of step 1

(b+c-a) (-b+c+a) (b-c+a)

(—————————————+—————————————)+———————————

((a-b)•(a-c)) ((b-c)•(b-a)) (c-a)•(c-b)

STEP

2

:

b - c + a

Simplify —————————————————

(c - a) • (c - b)

Equation at the end of step

2

:

(b+c-a) (-b+c+a) (b-c+a)

(—————————————+—————————————)+———————————

((a-b)•(a-c)) ((b-c)•(b-a)) (c-a)•(c-b)

STEP

3

:

Equation at the end of step 3

(b+c-a) (-b+c+a) (b-c+a)

(—————————————+———————————)+———————————

((a-b)•(a-c)) (b-c)•(b-a) (c-a)•(c-b)

STEP

4

:

-b + c + a

Simplify —————————————————

(b - c) • (b - a)

Equation at the end of step

4

:

(b+c-a) (-b+c+a) (b-c+a)

(—————————————+———————————)+———————————

((a-b)•(a-c)) (b-c)•(b-a) (c-a)•(c-b)

STEP

5

:

Equation at the end of step 5

(b+c-a) (-b+c+a) (b-c+a)

(———————————+———————————)+———————————

(a-b)•(a-c) (b-c)•(b-a) (c-a)•(c-b)

STEP

6

:

b + c - a

Simplify —————————————————

(a - b) • (a - c)

Equation at the end of step

6

:

(b+c-a) (-b+c+a) (b-c+a)

(———————————+———————————)+———————————

(a-b)•(a-c) (b-c)•(b-a) (c-a)•(c-b)

Step-by-step explanation:

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