Question

(b) A car moving along a straight track with a speed of 90km/h is brought to rest at
a distance of 200m. What is the retardation of the car?​

Answer 1

Answer:

-1.5625

Explanation:

u=90*5/18=25m/s

v=0

s=200m

a=?

v^2-u^2=2as

a=0-625/2*200

so a= --1.5625m/s^2

Answer 2

Answer:

see above picture. ....