Question

b) A compound has the following percentage composition by mass:
Carbon- 54.55%, Hydrogen- 9.09% and Oxygen- 36.26%. Its vapour density is 44. Find
the empirical formula and molecular formula of the compound. (H-1, C-12,0-16)
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11th

Chemistry

Organic Chemistry - Some Basic Principles and Techniques

Qualitative Analysis of Organic Compounds

A compound has the followin...

Chemistry

A compound has the following percentage composition by mass:

Carbon - 54.55%, Hydrogen - 9.09% and Oxygen - 36.26%. Its vapour density is 44. Find the Empirical and Molecular formula of the compound. (H = 1; C = 12; O = 16).

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Let amount of organic = 100 gm

amount of carbon = 54.55 g

amount of hydrogen = 9.09 g

Amount of oxygen = 36.26 g

number of mole of carbon =

12

34.55

=4.54583

number of mole of hydrogen =

1.018

9.09

=9

number of mole of oxygen =

16

36.26

=2.26

4.54833:9:2.26

2:4:1

organic compounds Empirical formula

=C

2

H

4

O

Molecular weight = 24+4+16=44

(for empirical)

Molecular weight = 2× vapour density

=2×44=88 g

To molecular formula be = C

4

H

8

O

2