(b)A force of 10N acts on a particle of mass 0.4kg for 5 seconds. Find the acceleration of the
particle and its change in momentum in 5 secods.
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Answer:
F=m×a
10= 0.4× a
a = 10/0.4
a= 25 ms^-2
Answered by
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force 10 n
mass 0.4 kg acceleration :? using the relation f= ma 10= 4/10×9 a= 100/4 =25 ms-2
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