Physics, asked by meghakumarisharma25, 7 months ago

b. A force of 30 N is applied to a body of mass 6 kg. Calculate the acceleration
produced on the body.
[ Ans: 5 m/s? ]
womotion of 60 m/s2 If the​

Answers

Answered by prasannaP3
2

Explanation:

F = 30N

M = 6kg

a = ?

F = MA

30 = 6×a

30/6 = a

a = 5

hence Acceleration is equal to 5 ( five )

Answered by ƦαíηвσωStαƦ
21

\huge{\underline{\overline{\mid{\mathfrak{\purple{\:\: SOLUTION\:\:} \mid}}}}}

\underline{ \mathfrak{ \: AnswEr:- \: }} \\ \\

 \sf{\blue{The\: required\: acceleration = \underline{ \: 5 \:m/s^2 \: }}}\\\\

\underline{ \mathfrak{ \: Given:- \: }} \\ \\

\text{ \orange{A force of 30 Newton is applied}} \\ \text{ \orange{ to a body of mass 6 kg.}} \\ \\

\underline{ \mathfrak{ \: Need \:\: to \:\: find:-\: }} \\ \\

\text{\red{The required acceleration = ?}}\\\\

\underline{ \mathfrak{ \: \:Formula \: \: used \: \: here:- \: \: }} \\

\: \: \: \: \: \: \: \: \: \: \: \sf{Force = Mass \times Acceleration} \\ \\

\underline{ \mathfrak{ \: Putting\:\:the\:\:values:- \: }} \\

\sf{ \longrightarrow \: 30 = 6 \times acceleration} \\ \\

\sf{ \longrightarrow \: 30 = 6\:acceleration} \\ \\

\sf{ \longrightarrow \: Acceleration = \dfrac{\cancel{30}}{\cancel{6}}\: }\\ \\

\sf{ \longrightarrow \: Acceleration = 5\:m/s^2}\\ \\

\underline{ \mathfrak{ \: \: Therefore:- \: \: }}

 \:\:\:\sf{\green{The\: required\: acceleration = \underline{ \: 5 \:m/s^2 \: }}}

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