Question

(b) A machine of length 90 cm is used to lift a load of 10 kgf. It has its fulcrum at a distance of 30 cm from the load . Calculate (i) the mechanical advantage of the machine (ii) the effort applied at the machine.


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Answer 1

Answer:

Given: L = 5 kgf, Load arm = 20 cm, Effort arm = 100 – 20 = 80 cm.

(Since the crow bar is the lever of first order with fulcrum in between the load and the effort).

(i) Mechanical advantage = Effort arm/Load arm = 80/20 = 4

(ii) M.A. = Load(L)/Effort(E)

∴ Effort = Load(L)/M.A. = 5/4

= 1.25 kgf.

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