Question

b) A particle increases its speed from
8 x 10^5 m/s to 1.1 x 10^6 m/s. What
is the percentage increase?​

Answer 1

Answer:

37.5% increase

Step-by-step explanation:

% increase = $\frac{[Final speed - Initial speed]}{Initial speed} * 100$

Initial speed = 8 x 10^5 m/s

Final speed = 1.1 x 10^6 m/s = 11 x 10^5 m/s

So,

Final speed - Initial speed = 11 x 10^5 m/s - 8 x 10^5 m/s

=  [11 - 8] x 10^5 m/s

= 3 x 10^5 m/s

Then divide this by initial speed,

=> 3 x 10^5 m/s ÷ 8 x 10^5 m/s = 3/8

Now multiply by 100,

=> 3/8 × 100 = 0.375 × 100 = 37.5%