b) An atom 'X has mass number 39 & its electronic configuration is 2, 8, 8, 1. Find the number of neutrons, protons, electrons present in atom 'X'.
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In neutral atom-protons=electrons=2+8+8+1=19
Neutrons=39-19=20
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In neutral atom-protons=electrons=2+8+8+1=19
In neutral atom-protons=electrons=2+8+8+1=19Neutrons=39-19=20
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