Chemistry, asked by ThePious, 2 days ago

b) An atom 'X has mass number 39 & its electronic configuration is 2, 8, 8, 1. Find the number of neutrons, protons, electrons present in atom 'X'.​

Answers

Answered by sumit83610
2

Answer:

In neutral atom-protons=electrons=2+8+8+1=19

Neutrons=39-19=20

Answered by ItxAttitude
5

@ItxATTITUDE

In neutral atom-protons=electrons=2+8+8+1=19

In neutral atom-protons=electrons=2+8+8+1=19Neutrons=39-19=20

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